Tutorials to solve Ratio Questions in Aptitude with Example

Tutorials to solve Ratio Questions in Aptitude


Ratio

Ratio represents the proportion in which a number contains another number. A ratio is represented by a/b or a:b. The duplication or division of every term of a proportion by the same non zero number does not influence the proportion.Subsequently, 3:5 is the same as 6:10 or 9:15 or 12:20 and so on.

Extent

The fairness of two proportions is called extent. As 2:3 = 6:9, we compose, 2:3::6:9 and we can say that 2,3,6,9 are in extent . Here 2 and 9 are called extremes while 3 and 6 are called implies.

In an extent, result of extremes=product of means.

Fourth Relative

if a:b::c:d, then d is known as the fourth relative to a,b and c.

Third Relative

if a:b::c:d, then c is known as the third relative to a and b.

Mean Relative

Mean relative is the middle of a and b.


Question of Ratio with solved example:

Q1. On the off chance that a:b=2:3 and b:c=5:7, discover a:c.

[A] 10:11
[B] 10:21
[C] 21:10
[D] 11:10

Answer – B

Explanation:

We have a/b = 2/3 and b/c = 5/7 
So a/c = (a/b*b/c) = (2/3*5/7) = 10/21 
So its demonstrate that a:c = 10:21

Q2. On the off chance that a:b=2:3 and b:c=5:7, discover a:b:c.

[A] 10:15:21
[B] 10:21:15
[C] 15:10:21
[D] 11:10:21

Answer – A

Explanation:

Here a/b = 2/3 and b/c = 5:7 = 3/5*5:3/5*7 = 3:21/5. 
So a:b=2:3 and b:c=3:21/5 
So a:b:c = 2:3:21/5 = 10:15:21. 

Q3. In the event that (5x+3y): (5x-3y) =3:1, then x:y=?

[A] 6:5
[B] 7:8
[C] 8:9
[D] 9:11

Answer – A

Explanation:

Here (5x+3y)/(5x-3y) = 3/1  
=> 5x+3y = 15x-9y
=> 10x = 12y
=> x/y = 12/10 = 6/5 
So x:y =6:5 

Q4. In the event that x:y= 5:3 ,then ( 8x-5y) : (8x+5y) = ?

[A] 6:11
[B] 7:11
[C] 8:11
[D] 5:11

Answer – D

Explanation:

Given x/y = 5/3 
Dividing numerator and denominator by y.
(8x-5y)/(8x+5y) = {8(x/y) - 5}/{8(x/y) + 5}
= {8*(5/3)-5}/{8*(5/3)+5}
= (40-15)/(40+15)
= 25/55
= 5/11 
So (8x-5y):(8x+5y)= 5:11

Q5. An aggregate of rs. 391 has been divided between a,b,c in the proportion 1/2 :2/3:3/4 , discover the offer of each..

[A] 102, 136, 153
[B] 112, 114, 123
[C] 114, 117, 129
[D] 122, 134, 123

Answer – A

Explanation:

We have a:b:c=1/2:2/3:3/4= 6:8:9. 
A share = (391*6/23) = 102 rs. 
B offer = (391*8/23) = 136 rs. 
C offer = (391*9/23) = 153 rs.

Q6. A blend contains liquor and water in the proportion 4:3, if 7 liter of water is added to the blend, the proportion of liquor and water gets to be 3:4. Discover the amount of liquor in the blend.

[A] 12 liters
[B] 13 liters
[C] 14 liters
[D] 15 liters

Answer – B

Explanation:

Let the amount of liquor and water be 4x liter and 3x liter separately.
At that point , 4x/3x + 7 = 3/4 
=> 16x = 9x+21 
=> 7x = 21 
so estimation of x is 3 
Amount of liquor in the blend is = 4*3 =12 liters. 

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